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Re: November 2022 cruise of Lio Kai
[Re: duckfat]
#291586
11/24/2022 03:24 AM
11/24/2022 03:24 AM
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Joined: Nov 2003
Posts: 1,422
New Jersey, USA
DanS
Traveler
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Traveler
Joined: Nov 2003
Posts: 1,422
New Jersey, USA
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VMG = V cos(TackAngle / 2) is correct only of there is no leeway or current. There is always leeway, more on a cat than a monohull. A charter cat will have as much as 10 degress of leeway. In that case, it would be VMG = V cos((TackAngle + 10)/ 2).
VMG is reduced by downwind current, increased with upwind current. I live in a universe where all phenomena can be explained with simple geometry, and silly complications like leeway and currents don't exist. Where do you live? Dan 
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