I am assuming that anything that a carrier might use would have a landing class of C so the maximum ILS glide path angle would be 3.6 degrees. A bit of math will calculate the maximum terrain height (OCS) at any distance from the runway. At 2 NM is 662' Quick Hill. OCS at that distance is 396' so about 270' will have to be taken off the top. At 3 nm is 852' Kingston Hill. OCS at 3nm is about 590' so another 260' will have to be removed from that mountain. I do not believe there is a grading budget for that in the bids.

BTW, Palm Springs has a 20 mile straight in 3 degree aproach to 13R and a 10 mile 3.2 degree with a 1.1 degree offset into 31L.

Last edited by GlennA; 06/02/2016 01:35 PM.
Travel is fatal to prejudice, bigotry, and narrow-mindedness, and many of our people need it sorely on these accounts. - Mark Twain